Neato

  • @nxdefiant
    link
    121 days ago

    x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?

    if this is setting y to the effect of bar() + running baz after, then:

    x = [bar(), baz()][0] or z

    might work

    and if you need y to be defined for later use:

    x = [(y:=bar()), baz()][0] or z

    but thats from memory, not sure if that will even run as written.

    if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.
    • @FizzyOrange@programming.dev
      link
      fedilink
      221 days ago

      foo isn’t a function, it’s a bool. But in any case, as you can see the answer is “with terrible hacks”. Python is not a functional language. It is imperative.

      • @nxdefiant
        link
        221 days ago

        Yeah, never said it was, just that if you really want to emulate that style you mostly can.